(d) AB is a chord of circle centre O. OE bisects AB. AD=12cm, ED = 8cm and OD = x. (1) Determine the (2) radius OB in terms E of x. Hence, calculate the length of the radius OB. 12 B 8 A 12 D​

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Given that OE bisects AB, we can conclude that AE = EB (since AO is equal to BO in a circle).

From the given information, we have AD = 12 cm and ED = 8 cm.

Since OE bisects AB, we can write AE + EB = AB. Therefore, AE = EB = 1/2 * AB = 1/2 * 12 = 6 cm.

Now, since OD is perpendicular to AE, we can use Pythagoras theorem to find the value of x (OD).

Thus, x^2 = AE^2 + OD^2

x^2 = 6^2 + 8^2

x^2 = 36 + 64

x^2 = 100

x = 10 cm

Now, we can determine the radius OB in terms of x using the Pythagoras theorem.

OB^2 = OE^2 + x^2

OB^2 = 12^2 + 10^2

OB^2 = 144 + 100

OB^2 = 244

OB = √244

OB = 2√61 cm

Therefore, the length of the radius OB is 2√61 cm.